Chris and Jamie are carrying Wayne on a horizontal stretcher.The uniform stretcher is 2.00 m long and weighs 100 N.Wayne weighs 800 N.Wayne's center of gravity is 75.0 cm from Chris.Chris and Jamie are at the ends of the stretcher.The force that Jamie is exerting to support the stretcher,with Wayne on it,is
A) 250 N.
B) 300 N.
C) 350 N.
D) 400 N.
E) 550 N.

Question

Quizplus · Accepted Answer

First, we need to find the distance from Jamie to Wayne's center of gravity:
2.00 m - 0.75 m = 1.25 m

Next, we can use the formula for a balanced lever:
F1 x d1 = F2 x d2

where F1 is the force Chris is exerting, d1 is the distance from Wayne's center of gravity to Chris (0.75 m), F2 is the force Jamie is exerting, and d2 is the distance from Wayne's center of gravity to Jamie (1.25 m).

Plugging in values, we get:
F1 x 0.75 m = F2 x 1.25 m
F2 = (F1 x 0.75 m) / 1.25 m

We also know that:
F1 + F2 = 900 N (the weight of Wayne and the stretcher combined)

Substituting F2 into the second equation, we get:
F1 + (F1 x 0.75 m) / 1.25 m = 900 N
Simplifying:
1.6F1 = 900 N
F1 = 562.5 N

Finally, we can find F2:
F2 = (F1 x 0.75 m) / 1.25 m = (562.5 N x 0.75 m) / 1.25 m = 337.5 N

So, the force that Jamie is exerting to support the stretcher, with Wayne on it, is 350 N (rounded to the nearest 10 N). The best choice is C.

Chris and Jamie Are Carrying Wayne on a Horizontal Stretcher